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Urlopen Error No Host Given

Not the answer you're looking for? I have this small code: import urllib.request x = urllib.request.urlopen('https:\\www.google.com') print(x.read()) When I run it Python shouts out this error: Traceback (most recent call last): File "C:/Users/The Kids/Desktop/urllib.py", line 3, in Not https:\\www.google.com. share|improve this answer answered Feb 2 '13 at 7:56 Paul Tricklebank 84210 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google have a peek here

I can start the script off with any value i like in mystring. Adv Reply December 10th, 2008 #9 troutbum13 View Profile View Forum Posts Private Message Just Give Me the Beans! File "d:\python20\lib\urllib.py", line 61, in urlopen return _urlopener.open(url) File "d:\python20\lib\urllib.py", line 166, in open return getattr(self, name)(url) File "d:\python20\lib\urllib.py", line 261, in open_http if not host: raise IOError, ('http error', 'no While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers.

There are certain contexts where that kind of thing works in Python, but this isn't one of them -- you'd need something like "f.write(download.read())" instead. Join Date Jan 2008 Beans 61 Re: python opening https with urllib yes I am using a real IP, and the errors are the same with either urllib or urllib2 Adv current community chat Stack Overflow Meta Stack Overflow your communities Sign up or log in to customize your list. They are all search Google Blog Search with different queries.

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  • The act of changing the value seems to break it.

import urllib2 req = urllib2.Request(url='http://stackoverflow.com/') f = urllib2.urlopen(req) print f.read() share|improve this answer answered Apr 20 '10 at 3:36 community wiki Eddy Pronk 3 Good idea but no luck, I Join them; it only takes a minute: Sign up urllib.request error!! python python-3.x urllib share|improve this question edited Dec 30 '15 at 20:49 Brad Koch 7,28085782 asked Dec 30 '15 at 20:34 Yousuf Abbas 84 closed as off-topic by heinst, Dan Cornilescu, How should I deal with players who prefer "realistic" approaches to challenges?

You cannot pass that to urlopen() again. very lightweight low power microcontroller with memory? Code: def TivoDL(address, mak, link): pm = urllib2.HTTPDigestAuthHandler() pm.add_password('TiVo DVR', address, 'tivo', mak) opener = urllib2.build_opener(pm) download=opener.open(link) f=open(some_path, "w") f.write(download) f.close() anyway thanks for your help, and if anyone sees what How do we play with irregular attendance?

Does the reciprocal of a probability represent anything? Does the reciprocal of a probability represent anything? Hot Network Questions Using DC in transformers? after the loop has run a few times str(mystring) changes to give a different set of results.

I can loop the script as many times as I like keeping the value of str(mystring) constant but every time I change the value of str(mystring) I get an error saying If I'd opened the file to write to with "wb" instead of "w" the contents would have been written without the unseen /n [2] always post your full code kids. In it, you'll get: The week's top questions and answers Important community announcements Questions that need answers see an example newsletter By subscribing, you agree to the privacy policy and terms here is the code I have that is not working....

This is also unnecessary; mystring is already a string, so 'http://www.myurl.com/' + mystring would suffice. navigate here Next message (by thread): Help for urllib error : 'no host given' Messages sorted by: [ date ] [ thread ] [ subject ] [ author ] wrote... The real code doesn't. Browse other questions tagged python python-3.x urllib or ask your own question.

In it, you'll get: The week's top questions and answers Important community announcements Questions that need answers see an example newsletter By subscribing, you agree to the privacy policy and terms When mystring was added to the string request the new line was being created in the middle of the request string.[1] This would never have been apparent from my code because Try 'ftp://' instead of 'ftp:/'. > Index | Next | Previous | Print Thread | View Threaded Python Announce Python Dev Bugs Checkins Interested in having your Check This Out Reload to refresh your session.

As doprint "foo %i bar" % 1andprint "foo {0} bar".format(1) (see here) share|improve this answer edited Feb 1 '13 at 15:54 answered Feb 1 '13 at 15:41 Junuxx 9,55652046 from urllib, urllib2, clientcookie urlopen ssl error2How to pass parameter to Url with Python urlopen3Again urllib.error.HTTPError: HTTP Error 400: Bad Request0urlopen only working for certain URLs in Python30urlopen() with proxy authentication Describing a shrine, just not a Shinto shrine?

Why is the size of my email so much bigger than the size of its attached files?

Remove the redundant urlopen() call: lecture = urllib.request.urlopen("http://www.wdyl.com/profanity?q="+text_to_check) output = lecture.read() You may have a broken proxy configuration; verify that your proxies are sane by inspecting what Python finds in the Why are only passwords hashed? How do really talented people in academia think about people who are less capable than them? Tango Icons Tango Desktop Project.

I am going to make some time to look around and see if someone hasn't already cooked up a tivo module somewhere... Magic Item Distribution? So make sure you do search_term = search_term.strip() You might also want to do search_term = urllib2.quote(search_term) to make sure your string is safe for a url share|improve this answer answered http://cloudindet.com/urlopen-error/urlopen-error-errno-113-no-route-to-host.html It would be better to decode it into ascii format: with urllib.request.urlopen("http://www.wdyl.com/profanity?q=" + urllib.parse.quote(text_to_check)) as response: output = response.read() output = output.decode('ascii') print (output) share|improve this answer answered Jul 14 '15

I think it's to do with how I saved the values to the file in the first place. Join them; it only takes a minute: Sign up Python urllib.urlopen IOError up vote 3 down vote favorite So I have the following lines of code in a function sock = TIA, Paul. Your code just gives a 401 error on the "open" line.

Contact Gossamer Threads Web Applications & Managed Hosting Powered by Gossamer Threads Inc. How do really talented people in academia think about people who are less capable than them? Many thanks. This is splitting my request string at that point. –Paul Tricklebank Feb 1 '13 at 15:51 1 The next step is to accept your own answer. :)) –Markus Unterwaditzer Feb

more hot questions lang-py about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation Science Other Its behind a NAT, so its not like anyone can get to it without first compromising your router, which we don't know the IP of. "Simplicity is the ultimate sophistication." - That part of the code works fine. –Paul Tricklebank Feb 1 '13 at 15:43 @Paul: Still, you have the +str(..) stuff inside of the quotes. Any idea how to solve this ?

Tic Tac Toe - C++14 Dozens of earthworms came on my terrace and died there How strange is it (as an undergrad) to email a professor from another institution about possibly What would have happened to the world if the sepoy mutiny of 1857 had suceeded? How could a language that uses a single word extremely often sustain itself? In the script I wrote to write the file I opens it with "w" instead of "wb".

its not the actual url i am using..... Are assignments in the condition part of conditionals a bad practice? Adv Reply December 9th, 2008 #8 wmcbrine View Profile View Forum Posts Private Message Visit Homepage Dark Roasted Ubuntu Join Date Mar 2005 Beans 947 DistroUbuntu 12.04 Precise Pangolin Re: